document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130595>Question 130595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> nine more than five times a number is equal to 3 less than seven times the number. Find the number.\r<BR>\n" );
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document.write( "if 2 subtracted from a number and this difference is tripled, the result is 6 more than the number. find the number\r<BR>\n" );
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document.write( "If 3 is added to a number and this sum is doubled, the result is 2 more than the number. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95388 by </B><A HREF=/tutors/aboutme.mpl?userid=cngriffith><B>cngriffith(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cngriffith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9+5x=7x-3    nine more than five times a number-rewrite as  9+5x<BR>\n" );
document.write( "             is equal to- rewrite as =<BR>\n" );
document.write( "             3 less than seven times the number-means 3 subtracted from 7x <BR>\n" );
document.write( "             rewrite as 7x-3 .   Now you have the equation to be solved.<BR>\n" );
document.write( "             Subtract 7x from both sides of the equation<BR>\n" );
document.write( "9-2x=-3<BR>\n" );
document.write( "             Subtract 9 from both sides.<BR>\n" );
document.write( "-2x=-12<BR>\n" );
document.write( "             Divide both sides by -2<BR>\n" );
document.write( "x=6 </SPAN>\n" );
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