document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130554>Question 130554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A truck can travel 150 miles in the same time that it takes a car to travel 200 miles.  If the truck's rate is 10 miles per hour slower than the car's, find the average rate for each.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95372 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 150/X=200/(X+10) NOW CROSS MULTIPLY.<BR>\n" );
document.write( "200X=150(X+10)<BR>\n" );
document.write( "200X=150X+1,500<BR>\n" );
document.write( "200X-150X=1,500<BR>\n" );
document.write( "50X=1,500<BR>\n" );
document.write( "X=1,500/50<BR>\n" );
document.write( "X=30 MPH FOR THE TRUCK.<BR>\n" );
document.write( "30+10=40 MPH FOR THE CAR.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "150/30=200/40<BR>\n" );
document.write( "5=5\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );