document.write( "Question 130560: the perimeter og a rectangle is 40m. the length of the rectangle is 4m less than twice the width. find the length \n" ); document.write( "
Algebra.Com's Answer #95370 by checkley71(8403)\"\" \"About 
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L=2W-4
\n" ); document.write( "2W+2(2W-4)=40
\n" ); document.write( "2W+4W-8=40
\n" ); document.write( "6W=40+8
\n" ); document.write( "6W=48
\n" ); document.write( "W=48/6
\n" ); document.write( "W=8 FOR THE WIDTH.
\n" ); document.write( "L=2*8-4=16-4=12 FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*8+2*12=40
\n" ); document.write( "16+24=40
\n" ); document.write( "40=40
\n" ); document.write( "
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