document.write( "Question 130560: the perimeter og a rectangle is 40m. the length of the rectangle is 4m less than twice the width. find the length \n" ); document.write( "
Algebra.Com's Answer #95370 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-4 \n" ); document.write( "2W+2(2W-4)=40 \n" ); document.write( "2W+4W-8=40 \n" ); document.write( "6W=40+8 \n" ); document.write( "6W=48 \n" ); document.write( "W=48/6 \n" ); document.write( "W=8 FOR THE WIDTH. \n" ); document.write( "L=2*8-4=16-4=12 FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "2*8+2*12=40 \n" ); document.write( "16+24=40 \n" ); document.write( "40=40 \n" ); document.write( " |