document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130567>Question 130567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A deal has two kinds of mets; one costs 90 cents a pound, the other 60 cents a pound. He wishes to make 50 pounds of a mixture that will cost 72 cents a pound. How many pounds of each kind should he use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95367 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .90X+.60(50-X)=.72*50<BR>\n" );
document.write( ".90X+30-.60X=36<BR>\n" );
document.write( ".30X=36-30<BR>\n" );
document.write( ".30X=6<BR>\n" );
document.write( "X=6/.30<BR>\n" );
document.write( "X=20 AMOUNT OF $.90 MEAT.<BR>\n" );
document.write( "50-20=30 AMOUNR OF $.60 MEAT.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".90*20+.60*30=36<BR>\n" );
document.write( "18+18=36<BR>\n" );
document.write( "36=36<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );