document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130566>Question 130566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tom can do a job in 3 hours, Dick in 4 hours, and Harry in 6 hours. If they do it together (and do not delay each other), how long does the job take? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95361 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of time it take all three working together to do the job<BR>\n" );
document.write( "Now we know that:<BR>\n" );
document.write( "Tom works at the rate of 1/3 job per hour<BR>\n" );
document.write( "Dick works at the rate of 1/4 job per hour<BR>\n" );
document.write( "Harry works at the rate of 1/6 job per hour\r<BR>\n" );
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document.write( "Together they work at the rate of 1/3 +1/4 +1/6 job per hour or<BR>\n" );
document.write( "8/24 + 6/24 +4/24=18/24=3/4 job per hr\r<BR>\n" );
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document.write( "Now our equation to solve is:\r<BR>\n" );
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document.write( "(3/4)*x=1 (1 job, that is)  multiply both sides by 4<BR>\n" );
document.write( "3x=4<BR>\n" );
document.write( "x=1 1/3 hours ---amount of time it takes all three working together\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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