document.write( "Question 130466: Kate's age exceeds twice Martha's age by 6 years. Eight years ago, four times Martha's age exceeded Kate's age by 6 years. Find their present ages. \n" ); document.write( "

Algebra.Com's Answer #95358 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=Martha's present age; x-8=Martha's age 8 years ago\r
\n" ); document.write( "\n" ); document.write( "Then 2x+6=Kates present age; (2x+6)-8=2x-2=Kates age 8 years ago
\n" ); document.write( "Now we are told that:\r
\n" ); document.write( "\n" ); document.write( "4(x-8)=2x-2+6 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "4x-32=2x+4 subtract 2x from each side and add 32 to each side\r
\n" ); document.write( "\n" ); document.write( "4x-2x-32+32=2x-2x+4+32 collect like terms\r
\n" ); document.write( "\n" ); document.write( "2x=36 divide both sides by 2
\n" ); document.write( "x=18-----------------Martha's present age
\n" ); document.write( "2x+6=2*18+6=42-------------------Kates present age\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "---Kate's age exceeds twice Martha's age by 6 years---
\n" ); document.write( "2*18+6=42
\n" ); document.write( "42=42
\n" ); document.write( "also
\n" ); document.write( "----Eight years ago, four times Martha's age exceeded Kate's age by 6 years---
\n" ); document.write( "4*(18-8)=(42-8)+6
\n" ); document.write( "4*10=44+6
\n" ); document.write( "40=40\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );