document.write( "Question 130551This question is from textbook algebra
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\n" ); document.write( "An investment of $1500 paid interest of $45 during a certain period. How much interest would an investment of $2000 invested at the same rate for the same length of time pay?
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Algebra.Com's Answer #95349 by bucky(2189)\"\" \"About 
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Since the interest rate does not change and the period of investment remains unchanged, you
\n" ); document.write( "can do this problem by setting up a proportion:
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\n" ); document.write( "interest (I) is to invested principal (P) as interest (I) is to invested principal (P)
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\n" ); document.write( "Which in equation form becomes:
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\n" ); document.write( "\"I%5B1%5D%2FP%5B1%5D+=+I%5B2%5D%2FP%5B2%5D\"
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\n" ); document.write( "On the left side of this equation we can substitute information from the problem. The first
\n" ); document.write( "amount of interest is $45 and the principal invested is $1500. Substituting these values results
\n" ); document.write( "in:
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\n" ); document.write( "\"45%2F1500+=+I%5B2%5D%2FP%5B2%5D\"
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\n" ); document.write( "On the right side of the equation we know that the new principal is $2000. So we can substitute
\n" ); document.write( "that amount to get the equation:
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\n" ); document.write( "\"45%2F1500+=+I%5B2%5D%2F2000\"
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\n" ); document.write( "Proportions of this form can be solved by first doing cross multiplication. Multiply the
\n" ); document.write( "each numerator by the denominator on the other side and set the two products equal.
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\n" ); document.write( "So in this problem multiply the numerator \"45\" by the denominator on the other side \"%282000%29\"
\n" ); document.write( "and you get \"%2845%2A2000%29\". Then multiply the numerator \"I%5B2%5D\" by the denominator on the other
\n" ); document.write( "side \"%281500%29\" and you get \"1500%2AI%5B2%5D\". Set the two products equal and you have the
\n" ); document.write( "equation:
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\n" ); document.write( "\"1500%2AI%5B2%5D=+45%2A2000\"
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\n" ); document.write( "Solve for \"I%5B2%5D\" by dividing both sides by \"1500\" and the equation becomes:
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\n" ); document.write( "\"I%5B2%5D+=+%2845%2A2000%29%2F1500\"
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\n" ); document.write( "Do the multiplication and division on the right side and you get the answer:
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\n" ); document.write( "\"I%5B2%5D+=+60\"
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\n" ); document.write( "This tells you that at the same rate of interest and for the same period if $1500 earns $45,
\n" ); document.write( "then an investment of $2000 will earn $60.
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\n" ); document.write( "Hope this helps you to understand the problem.
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