document.write( "Question 130537This question is from textbook Introductory Algebra
\n" ); document.write( ": I'll try one more time...\r
\n" ); document.write( "\n" ); document.write( "12/sqrt(5x+6) = sqrt(2x+5)\r
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Algebra.Com's Answer #95326 by oscargut(2103)\"\" \"About 
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\n" ); document.write( "12/sqrt(5x+6) = sqrt(2x+5)
\n" ); document.write( "then
\n" ); document.write( "12=sqrt(5x+6)sqrt(2x+5)
\n" ); document.write( "then
\n" ); document.write( "12^2=(sqrt(5x+6)sqrt(2x+5))^2
\n" ); document.write( "then
\n" ); document.write( "144=(5x+6)(2x+5)
\n" ); document.write( "then
\n" ); document.write( "10x^2+37x+30=144
\n" ); document.write( "then
\n" ); document.write( "10x^2+37x-114=0
\n" ); document.write( "then
\n" ); document.write( "\"x+=+%28-37+%2B-+sqrt%28+37%5E2-4%2A10%2A%28-114%29+%29%29%2F%282%2A10%29+\"
\n" ); document.write( "then
\n" ); document.write( "\"x+=+%28-37+%2B-+sqrt%28+5929+%29%29%2F20+\"
\n" ); document.write( "then
\n" ); document.write( "\"x+=+%28-37+%2B-+77%29%2F20+\"
\n" ); document.write( "then x=-5.5 or x=2
\n" ); document.write( "but in the original equation x=-5.5 produces a sqrt of a negative number
\n" ); document.write( "so the only solution is\r
\n" ); document.write( "\n" ); document.write( "x=2
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