document.write( "Question 130537This question is from textbook Introductory Algebra
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document.write( ": I'll try one more time...\r
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document.write( "12/sqrt(5x+6) = sqrt(2x+5)\r
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document.write( "Thanks!
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Algebra.Com's Answer #95326 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "12/sqrt(5x+6) = sqrt(2x+5) \n" ); document.write( "then \n" ); document.write( "12=sqrt(5x+6)sqrt(2x+5) \n" ); document.write( "then \n" ); document.write( "12^2=(sqrt(5x+6)sqrt(2x+5))^2 \n" ); document.write( "then \n" ); document.write( "144=(5x+6)(2x+5) \n" ); document.write( "then \n" ); document.write( "10x^2+37x+30=144 \n" ); document.write( "then \n" ); document.write( "10x^2+37x-114=0 \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "then x=-5.5 or x=2 \n" ); document.write( "but in the original equation x=-5.5 produces a sqrt of a negative number \n" ); document.write( "so the only solution is\r \n" ); document.write( "\n" ); document.write( "x=2 \n" ); document.write( " \n" ); document.write( " |