document.write( "Question 130472: Tim is 4 years older than one-third of Juan's age. In 10 years, Juan will be 6 years older than twice as old as Tim is now. How old is each now? \n" ); document.write( "

Algebra.Com's Answer #95325 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x= Juan's current age; x+10=Juan's age in 10 years
\n" ); document.write( "Then (1/3)x+4=Tim's current age; \r
\n" ); document.write( "\n" ); document.write( "Now we are told that:
\n" ); document.write( "x+10=2{(1/3)x+4}+6 get rid of brackets
\n" ); document.write( "x+10=(2/3)x+8+6 =(2/3)x+14 multiply each side by 3\r
\n" ); document.write( "\n" ); document.write( "3x+30=2x+42 subtract 30 and also 2x from each side\r
\n" ); document.write( "\n" ); document.write( "3x-2x+30-30=2x-2x+42-30 collect like terms\r
\n" ); document.write( "\n" ); document.write( "x=12----------------Juan's current age
\n" ); document.write( "(1/3)x+4=(1/3)*12+4=8 -------Tim's current age\r
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\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "---4 years older than 1/3 of Juan's age=(1/3)*12+4=8
\n" ); document.write( "8=8\r
\n" ); document.write( "\n" ); document.write( "---In 10 years, Juan will be 6 years older than twice as old as Tim is now.
\n" ); document.write( "12+10=22
\n" ); document.write( "2*8+6=22
\n" ); document.write( "22=22\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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