document.write( "Question 130494: Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that Katie is now. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #95302 by stanbon(75887)\"\" \"About 
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Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that Katie is now. How old is each now?
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\n" ); document.write( "Four yrs. ago DATA:
\n" ); document.write( "Let Anne's age be \"x\" yrs. old : Katie's age was was \"2x\" yrs.
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\n" ); document.write( "In 6 years DATA: (10 years after 4 years ago)
\n" ); document.write( "Anne will be \"x+10\" yrs old ; Katie will be \"2x+10\" yrs old.
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\n" ); document.write( "Now DATA: (4 years after 4 years ago)
\n" ); document.write( "Anne's age is \"x+4\" years ; Katie's age is \"2x+4\" years.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "x+10 = 2x+4
\n" ); document.write( "x = 6
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\n" ); document.write( "NOW Ages:
\n" ); document.write( "Anne's age = x+4 = 6+4 = 10 years
\n" ); document.write( "Katie's age = 2x+4 = 2*6+4 = 16 years
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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