document.write( "Question 130494: Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that Katie is now. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #95302 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that Katie is now. How old is each now? \n" ); document.write( "------------ \n" ); document.write( "Four yrs. ago DATA: \n" ); document.write( "Let Anne's age be \"x\" yrs. old : Katie's age was was \"2x\" yrs. \n" ); document.write( "------------------- \n" ); document.write( "In 6 years DATA: (10 years after 4 years ago) \n" ); document.write( "Anne will be \"x+10\" yrs old ; Katie will be \"2x+10\" yrs old. \n" ); document.write( "------------------- \n" ); document.write( "Now DATA: (4 years after 4 years ago) \n" ); document.write( "Anne's age is \"x+4\" years ; Katie's age is \"2x+4\" years. \n" ); document.write( "-------------------------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "x+10 = 2x+4 \n" ); document.write( "x = 6 \n" ); document.write( "---------- \n" ); document.write( "NOW Ages: \n" ); document.write( "Anne's age = x+4 = 6+4 = 10 years \n" ); document.write( "Katie's age = 2x+4 = 2*6+4 = 16 years \n" ); document.write( "=========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |