document.write( "Question 130494: Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that Katie is now. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #95301 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let k= Katie's age now, a= Anne's age now. \n" ); document.write( "k-4=2(a-4) \n" ); document.write( "k-4=2a-8 \n" ); document.write( "k-2a=-4 \n" ); document.write( ". \n" ); document.write( "k=a+6 \n" ); document.write( ". \n" ); document.write( "a+6-2a=-4 Substitute a+6 for k in the 1st equation. \n" ); document.write( "-a=-10 \n" ); document.write( "a=10 y.o. \n" ); document.write( "k=10+6=16 y.o. \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |