document.write( "Question 130409: An auditor reviewed 25 oral surgery insurance claims from a particular surgical office, determining
\n" ); document.write( "that the mean out-of-pocket patient billing above the reimbursed amount was $275.66 with a
\n" ); document.write( "standard deviation of $78.11. (a) At the 5 percent level of significance, does this sample prove a
\n" ); document.write( "violation of the guideline that the average patient should pay no more than $250 out-of-pocket?
\n" ); document.write( "State your hypotheses and decision rule. (b) Is this a close decision?
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Algebra.Com's Answer #95288 by stanbon(75887)\"\" \"About 
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An auditor reviewed 25 oral surgery insurance claims from a particular surgical office, determining that the mean out-of-pocket patient billing above the reimbursed amount was $275.66 with a standard deviation of $78.11.
\n" ); document.write( "(a) At the 5 percent level of significance, does this sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket?
\n" ); document.write( "State your hypotheses and decision rule.
\n" ); document.write( "Ho: mu= 250
\n" ); document.write( "Ha: mu > 250
\n" ); document.write( "Critical value for alpha = 5% and df = 24 is t = 1.711
\n" ); document.write( "Test statistic:
\n" ); document.write( "t(275.66) = (275.66-250)/[78.11/sqrt(25)] = 25.66*5/78.11 = 1.643
\n" ); document.write( "Since the test statistic is less than the critical value Fail to
\n" ); document.write( "reject Ho.
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\n" ); document.write( "(b) Is this a close decision?
\n" ); document.write( "The p-value for t= 1.643 is 0.05675...
\n" ); document.write( "Very close to 5% which is the breakpoint for deciding rejection of Ho.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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