document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130391>Question 130391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a world problem, not sure if I came up with the right answer. Could I have some help on this, thanks. The good seed flower shop sells its own brand of fertilizer. It mixes one brand of fertilizer that contains 7% nitrogen with another that contains 8% nitrogen. The resulting mixture contains 7.7% nitrogen. How many pounds of the 8% fertilizer must be used to make 200 pounds of the 7.7% mixture? I have 98.6 Could you let me know if it is correct. Thank you, I appreciate the help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95259 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since 7.7 is closer to 8 than to 7, there must be more of the 8% (more than 100lb)\r<BR>\n" );
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document.write( "let x=\"pounds of 8%\", so 200-x=\"pounds of 7%\"\r<BR>\n" );
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document.write( "(8%)(x)+(7%)(200-x)=(7.7%)(200) __ .08x+14-.07x=15.4 __ .01x=1.4 </SPAN>\n" );
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