document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130391>Question 130391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a world problem, not sure if I came up with the right answer. Could I have some help on this, thanks. The good seed flower shop sells its own brand of fertilizer. It mixes one brand of fertilizer that contains 7% nitrogen with another that contains 8% nitrogen. The resulting mixture contains 7.7% nitrogen. How many pounds of the 8% fertilizer must be used to make 200 pounds of the 7.7% mixture? I have 98.6 Could you let me know if it is correct. Thank you, I appreciate the help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95257 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .08X+.07(200-X)=.077*200<BR>\n" );
document.write( ".08X+14-.07X=15.4<BR>\n" );
document.write( ".01X=15.4-14<BR>\n" );
document.write( ".01X=1.4<BR>\n" );
document.write( "X=1.4/.01<BR>\n" );
document.write( "X=140 POUNDS OF 8% FERTILIZER IS NEEDED.<BR>\n" );
document.write( "200-140=60 POUNDS OF 7% IS NEEDED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".08*140+.07*60=.077*200<BR>\n" );
document.write( "11.2+4.2=15.4<BR>\n" );
document.write( "15.4=15.4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );