document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130390>Question 130390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a word problem, think I have an answer. Could you let me know for sure.<BR>\n" );
document.write( "A chemist is making 200 Liters of solution that is 62% acid. He is mixing 80% acid solution with a 30% acid solution. How much of the 80% acid solution will he use? I have 68 liters. Could you let me know if this is correct, thank you I really appreciate the help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95254 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> here is a \"rule of thumb\" for mixture problems<BR>\n" );
document.write( "__ the average of 80% and 30% is 55% __ this is what you get mixing them in equal parts<BR>\n" );
document.write( "__ since the mixture is supposed to be 62%, it must be more than half of the 80%<BR>\n" );
document.write( "__ so the amount of 80% is more than 100L\r<BR>\n" );
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document.write( "let x=\"amount of 80%\", so 200-x=\"amount of 30%\"\r<BR>\n" );
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document.write( "(80%)(x)+(30%)(200-x)=(62%)(200) __ .8x+60-.3x=124 __ .5x=64 </SPAN>\n" );
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