document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130329>Question 130329</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395937787/algebrahomeworkh>Algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> page 505 # 57\r<BR>\n" );
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document.write( "6.5 log5 3x = 20\r<BR>\n" );
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document.write( "can you help me in the steps to solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95234 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> dividing by 6.5 __ log5(3x)=40/13 __ taking antilog __ 3x=5^(40/13)\r<BR>\n" );
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document.write( "dividing by 3 __ x=(5^(40/13))/3 </SPAN>\n" );
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