document.write( "Question 130317: I can't seem to find the solution to this problem. I would appreciate some guidance. Thank you. A solution containing 30% insecticide is to be mixed with a solution containing 50% insecticide to make 200 L of a solution containing 42% insecticide. How much of the 50% insecticide solution should be used? liters \n" ); document.write( "
Algebra.Com's Answer #95229 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! let x=\"liters of 50%\", so 200-x=\"liters of 30%\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x(50%)+(200-x)(30%)=200(42%) __ .5x+60-.3x=84 __ .2x=24 \n" ); document.write( " |