document.write( "Question 130389This question is from textbook algebra
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\n" ); document.write( "The question for this is: for the function f(x)= x^2 -2x+1\r
\n" ); document.write( "\n" ); document.write( "a)find f(0)\r
\n" ); document.write( "\n" ); document.write( "b) solve f(x)=0\r
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Algebra.Com's Answer #95219 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a)\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E2-2x%2B1\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"f%280%29=%280%29%5E2-2%280%29%2B1\" Plug in \"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%280%29=0-2%2A0%2B1\" Raise 0 to the 2nd power to get 0\r
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\n" ); document.write( "\n" ); document.write( "\"f%280%29=0-0%2B1\" Multiply 2 and 0 to get 0\r
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\n" ); document.write( "\n" ); document.write( "\"f%280%29=0%2B1\" Subtract 0 from 0 to get 0\r
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\n" ); document.write( "\n" ); document.write( "\"f%280%29=1\" Add 0 and 1 to get 1\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E2-2x%2B1\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2-2x%2B1\" Plug in \"f%28x%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0=%28x-1%29%28x-1%29\" Factor the right side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"x-1=0\" or \"x-1=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=1\" or \"x=1\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "Since we have a repeating answer, our only answer is \"x=1\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=x%5E2-2x%2B1\" we can see that the only root is \"x=1\". So this visually verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+x%5E2-2x%2B1%29+\"
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