document.write( "Question 130378This question is from textbook algebra
\n" ); document.write( ": Hi! How are you all Today?
\n" ); document.write( "So I am having a bit of trouble with this question.
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Algebra.Com's Answer #95212 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let's denote the first point (5,3) as . In other words, and \r
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\n" ); document.write( "\n" ); document.write( "Now let's denote the second point (-2,-3) as . In other words, and \r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-3-3%29%2F%28-2-5%29\" Plug in \"y%5B2%5D=-3\",\"y%5B1%5D=3\",\"x%5B2%5D=-2\",\"x%5B1%5D=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=-6%2F-7\" Subtract the terms in the numerator \"-3-3\" to get \"-6\". Subtract the terms in the denominator \"-2-5\" to get \"-7\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=6%2F7\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line through the points (5,3) and (-2,-3) is \"m=6%2F7\"
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