document.write( "Question 19668: (10 pts) A car starts on a trip and travels at a speed of 55 mph. Two hours later, a second car starts on the same trip and travels at a speed of 65 mph.
\n" ); document.write( "When the second car has been on the road for t hours, the first car has traveled ____ miles and the second car has traveled ____miles.
\n" ); document.write( "At time t the distance between the first car and the second car is_____ miles.
\n" ); document.write( "The ratio of the distance the second car has traveled and the distance the first car has traveled is ______.
\n" ); document.write( "The second car catches up with the first car _____ hours after the departure of the first car. (Those are some determined drivers!) \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #9520 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
(10 pts) A car starts on a trip and travels at a speed of 55 mph. Two hours later, a second car starts on the same trip and travels at a speed of 65 mph. \r
\n" ); document.write( "\n" ); document.write( "let t be the time
\n" ); document.write( "55(t+2)=65t
\n" ); document.write( "55t+110=65t
\n" ); document.write( "110=10t
\n" ); document.write( "t=11
\n" ); document.write( "11+2 = 13
\n" ); document.write( "
\n" );