document.write( "Question 19668: (10 pts) A car starts on a trip and travels at a speed of 55 mph. Two hours later, a second car starts on the same trip and travels at a speed of 65 mph.
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document.write( "When the second car has been on the road for t hours, the first car has traveled ____ miles and the second car has traveled ____miles.
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document.write( "At time t the distance between the first car and the second car is_____ miles.
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document.write( "The ratio of the distance the second car has traveled and the distance the first car has traveled is ______.
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document.write( "The second car catches up with the first car _____ hours after the departure of the first car. (Those are some determined drivers!) \r
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Algebra.Com's Answer #9520 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! (10 pts) A car starts on a trip and travels at a speed of 55 mph. Two hours later, a second car starts on the same trip and travels at a speed of 65 mph. \r \n" ); document.write( "\n" ); document.write( "let t be the time \n" ); document.write( "55(t+2)=65t \n" ); document.write( "55t+110=65t \n" ); document.write( "110=10t \n" ); document.write( "t=11 \n" ); document.write( "11+2 = 13 \n" ); document.write( " |