document.write( "Question 130316This question is from textbook Algebra 1
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\n" ); document.write( " Translate to a system of equations and solve.
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Algebra.Com's Answer #95184 by solver91311(24713)\"\" \"About 
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Let's say we have n nickels and d dimes. That means that:\r
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\n" ); document.write( "\n" ); document.write( "\"n+%2B+d+=+304\", because that is the number of coins we have altogether.\r
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\n" ); document.write( "\n" ); document.write( "A nickel is worth 5 cents, so the value of all of the nickels is 5n cents. Likewise, the value of all of the dimes is 10d.\r
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\n" ); document.write( "\n" ); document.write( "Just because I don't like mucking about with decimal coefficients, let's change the total amount of money from $22.40 to 2240 cents.\r
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\n" ); document.write( "\n" ); document.write( "Now we can say that \"5n%2B10d=2240\"\r
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\n" ); document.write( "\n" ); document.write( "We can re-state the first equation by solving it for either of the variables. Let's solve it for d: \"d=304-n\"\r
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\n" ); document.write( "\n" ); document.write( "Now take this expression for d and substitute it into the second equation:\r
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\n" ); document.write( "\n" ); document.write( "\"5n%2B10%28304-n%29=2240\"\r
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\n" ); document.write( "\n" ); document.write( "\"5n-10n%2B3040=2240\"\r
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\n" ); document.write( "\n" ); document.write( "\"-5n=2240-3040\"\r
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\n" ); document.write( "\n" ); document.write( "\"-5n=-800\"\r
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\n" ); document.write( "\n" ); document.write( "\"n=160\"\r
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\n" ); document.write( "\n" ); document.write( "So there were 160 nickels.\r
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\n" ); document.write( "\n" ); document.write( "If there were 160 nickels, then there were 144 dimes (304 - 160). 144 dimes is $14.40, 160 nickels is $8.00. $14.40 + $8.00 = $22.40. Answer checks.
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