document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128955>Question 128955</A>: <I><SPAN STYLE=\"word-break: break-all;\"> okay this problem says to solve by completing the square, but the odd numbers are throwing me off, and this problem is not to be graphed, so no problem on here really helped me, the problem is:\r<BR>\n" );
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document.write( "1x(1x)+11x-6=0\r<BR>\n" );
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document.write( "any help on how to solve it would be greatly appreciated, this is for a college algebra course </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95175 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think you mean <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B11x-6=0 ALIGN=MIDDLE  ALT=\"x%5E2%2B11x-6=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 1:  Add the additive inverse of the constant term to both sides.  For this problem, add 6 to both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B11x=6 ALIGN=MIDDLE  ALT=\"x%5E2%2B11x=6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 2:  Divide through by the coefficient on the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2 ALIGN=MIDDLE  ALT=\"x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > term.  For this problem, that is 1, so you don't have to do anything.\r<BR>\n" );
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document.write( "Step 3:  Divide the coefficient on the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" > term by 2.  For this problem, that becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=11%2F2 ALIGN=MIDDLE  ALT=\"11%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Step 4:  Square the result of step 3.  For this problem:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=121%2F4 ALIGN=MIDDLE  ALT=\"121%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 5:  Add the result of step 4 to both sides of the equation.  For this problem:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B11x%2B%28121%2F4%29=6%2B%28121%2F4%29 ALIGN=MIDDLE  ALT=\"x%5E2%2B11x%2B%28121%2F4%29=6%2B%28121%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B11x%2B%28121%2F4%29=%2824%2B121%29%2F4 ALIGN=MIDDLE  ALT=\"x%5E2%2B11x%2B%28121%2F4%29=%2824%2B121%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B11x%2B%28121%2F4%29=145%2F4 ALIGN=MIDDLE  ALT=\"x%5E2%2B11x%2B%28121%2F4%29=145%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 6:  Factor the left:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B%2811%2F2%29%29%5E2=145%2F4 ALIGN=MIDDLE  ALT=\"%28x%2B%2811%2F2%29%29%5E2=145%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Step 7: Take the square root of both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B%2811%2F2%29=sqrt%28145%2F4%29 ALIGN=MIDDLE  ALT=\"x%2B%2811%2F2%29=sqrt%28145%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B11%2F2=-sqrt%28145%2F4%29 ALIGN=MIDDLE  ALT=\"x%2B11%2F2=-sqrt%28145%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28-11%2Bsqrt%28145%29%29%2F2 ALIGN=MIDDLE  ALT=\"x=%28-11%2Bsqrt%28145%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28-11-sqrt%28145%29%29%2F2 ALIGN=MIDDLE  ALT=\"x=%28-11-sqrt%28145%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Yes, these numbers are a horror, but certainly prettier than what you generally encounter in real life situations.  By the way, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28145%29 ALIGN=MIDDLE  ALT=\"sqrt%28145%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is reduced to simplest terms because there are no perfect square factors of 145 -- the prime factorization is 5 * 29. </SPAN>\n" );
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