document.write( "Question 130296: Looking at \"f%28x%29=-0.2x%5E2%2B12x%2B11\"\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic equation to determine the last day that tickets will be sold. (Note: Write your answer in terms of the number of days after ticket sales begin.)
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Algebra.Com's Answer #95157 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The last day of ticket sales will correspond to the rightmost zero. So we need to find the zeros\r
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\n" ); document.write( "\n" ); document.write( "\"y=-0.2x%5E2%2B12x%2B11\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"0=-0.2x%5E2%2B12x%2B11\" Set y equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"10%280%29=10%28-0.2x%5E2%2B12x%2B11%29\" Multiply both sides by 10 to get rid of the decimal number\r
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\n" ); document.write( "\n" ); document.write( "\"0=-2x%5E2%2B120x%2B110\" Distribute and multiply \r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"-2%2Ax%5E2%2B120%2Ax%2B110=0\" ( notice \"a=-2\", \"b=120\", and \"c=110\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+%28120%29%5E2-4%2A-2%2A110+%29%29%2F%282%2A-2%29\" Plug in a=-2, b=120, and c=110\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+14400-4%2A-2%2A110+%29%29%2F%282%2A-2%29\" Square 120 to get 14400 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+14400%2B880+%29%29%2F%282%2A-2%29\" Multiply \"-4%2A110%2A-2\" to get \"880\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+sqrt%28+15280+%29%29%2F%282%2A-2%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+4%2Asqrt%28955%29%29%2F%282%2A-2%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B-+4%2Asqrt%28955%29%29%2F-4\" Multiply 2 and -2 to get -4\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-120+%2B+4%2Asqrt%28955%29%29%2F-4\" or \"x+=+%28-120+-+4%2Asqrt%28955%29%29%2F-4\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"x=-120%2F-4%2B4%2Asqrt%28955%29%2F-4\" or \"x=-120%2F-4-4%2Asqrt%28955%29%2F-4\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x=30-sqrt%28955%29\" or \"x=30%2Bsqrt%28955%29\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=-0.903074280724887\" or \"x=60.9030742807249\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=-0.903074280724887\" or \"x=60.9030742807249\"\r
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\n" ); document.write( "\n" ); document.write( "So the last day of ticket sales will be on the 60th day
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