document.write( "Question 130175: Solve: logbase2(1-x)+logbase2(4x+1)=0 \n" ); document.write( "

Algebra.Com's Answer #95111 by stanbon(75887) $\"\"$ $\"About$

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Solve: logbase2(1-x)+logbase2(4x+1) = 0
\n" ); document.write( "log2[(1-x)(4x+1)] = 0
\n" ); document.write( "(1-x)(4x+1) = 2^0
\n" ); document.write( "-4x^2+3x+1 = 1
\n" ); document.write( "4x^2-3x = 0
\n" ); document.write( "x(4x-3)=0
\n" ); document.write( "x = 0 or x = 3/4
\n" ); document.write( "Checking:
\n" ); document.write( "If x = 0:
\n" ); document.write( "log2(1)+log2)1) = 0
\n" ); document.write( "True
\n" ); document.write( "--------------
\n" ); document.write( "If x = 3/4
\n" ); document.write( "log2(1-(3/4)) + log2(4(3/4)+1) = 0
\n" ); document.write( "log2(1/4) + log2(4) = 0
\n" ); document.write( "-2 + 2 = 0
\n" ); document.write( "True
\n" ); document.write( "===========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

\n" );