document.write( "Question 130093: Pete won $10 000 in a lottery. He invested his winnings, part at 10% per annum and part at 11% per annum. If the total interest earned was %1060, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #95110 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .11X+.10(10,000-X)=1,060 \n" ); document.write( ".11X+1,000-.10X=1,060 \n" ); document.write( ".01X=1,060-1,000 \n" ); document.write( ".01X=60 \n" ); document.write( "X=60/.01 \n" ); document.write( "X=6,000 AMOUNT INVESTED @ 11%. \n" ); document.write( "10,000-6,000=4,000 INVESTED @ 10%. \n" ); document.write( "PROOF \n" ); document.write( ".11*6,000+.10*4,000=1,060 \n" ); document.write( "660+400=1,060 \n" ); document.write( "1,060=1,060 \n" ); document.write( " |