document.write( "Question 19632: Please help me solve this:\r
\n" ); document.write( "\n" ); document.write( " 2b+a=11
\n" ); document.write( " a-b=5
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Algebra.Com's Answer #9506 by xcentaur(357)\"\" \"About 
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a+2b=11
\n" ); document.write( "a-b=5
\n" ); document.write( "


\n" ); document.write( "multiply the second equation by 2.when you multiply an equation by a number,the equation still remains the same,because you could divide that and get the original equation back again


\n" ); document.write( "now we have
\n" ); document.write( "a+2b=11
\n" ); document.write( "2a-2b=10
\n" ); document.write( "


\n" ); document.write( "Add the two equations,
\n" ); document.write( "(a+2b+2a-2b)=11+10
\n" ); document.write( "3a=21
\n" ); document.write( "a=7
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\n" ); document.write( "From equation 1,
\n" ); document.write( "a+2b=11
\n" ); document.write( "2b=11-a
\n" ); document.write( "2b=11-7
\n" ); document.write( "2b=4
\n" ); document.write( "b=2
\n" ); document.write( "


\n" ); document.write( "a=7,b=2
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\n" ); document.write( "-Prabhat \n" ); document.write( "

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