document.write( "Question 130123: If the distance traveled is 5x^3 - 6x^2+3x+14 miles and the rate is x+1 per hour, what is the time traveled?\r
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Algebra.Com's Answer #95056 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the formula \"d=r%2At\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=r%2At\" Start with the given formula\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E3+-+6x%5E2%2B3x%2B14=%28x%2B1%29%2At\" Plug in \"d=5x%5E3+-+6x%5E2%2B3x%2B14\" and \"r=x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%285x%5E3+-+6x%5E2%2B3x%2B14%29%2F%28x%2B1%29=t\" Divide both sides by \"x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28x%2B1%29%285x%5E2+-+11x+%2B+14%29%29%2F%28x%2B1%29=t\" Factor \"5x%5E3+-+6x%5E2%2B3x%2B14\" to get \"%28x%2B1%29%285x%5E2+-+11x+%2B+14%29\" (note: you can use a graphing calculator to help you do this)\r
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\n" ); document.write( "\n" ); document.write( "\"%28cross%28x%2B1%29%285x%5E2+-+11x+%2B+14%29%29%2Fcross%28x%2B1%29=t\" Cancel like terms\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2+-+11x+%2B+14=t\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"t=5x%5E2+-+11x+%2B+14\"
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