document.write( "Question 130118: Hi! i have a question on my math homework i have to find the circumcenter of a triangle whose points are L(83,15) S(196,123) and B(22,123). i have found the midpoints which are on line: LS is (139.5,69), SB is (109,123), and LB is 52.5,69). then i found the slope of each line which is: LS 108/113, SB 0, and LB -108/61. then i have tried to find the perpendicular bisector of each but every time i do the same problem i have came out with a different number that equals b. i have tried for a few hours on this problem and i would aprieciate if you could help me find what X (of the circumcenter) would be. Thank you \n" ); document.write( "
Algebra.Com's Answer #95052 by stanbon(75887) ![]() You can put this solution on YOUR website! The circumcenter is the center of a triangle's circumcircle. It can be found as the intersection of the perpendicular bisectors. \n" ); document.write( "----------------------------------------------------- \n" ); document.write( "i have to find the circumcenter of a triangle whose points are \n" ); document.write( "L(83,15), S(196,123) and B(22,123). \n" ); document.write( "i have found the midpoints which are on line: \n" ); document.write( "LS is (139.5,69), SB is (109,123), and LB is (52.5,69). \n" ); document.write( "then i found the slope of each line which is: \n" ); document.write( "LS 108/113, SB 0, and LB -108/61 \n" ); document.write( "----------------------------------- \n" ); document.write( "Equations: \n" ); document.write( "Perpendicular bisector of LS: \n" ); document.write( "Finding the y-intercept. \n" ); document.write( "69 = (-113/108)139.5 + b \n" ); document.write( "b = 214.9583333 \n" ); document.write( "Equation of the perp/bisector of LS: y = (-113/108)x-214.959333 \n" ); document.write( "------------------------- \n" ); document.write( "Perpendicular bisector of SB \n" ); document.write( "Since SB has slope = 0, the perpendicular is a vertical line thru the \n" ); document.write( "midpoint (109,123) \n" ); document.write( "Equation of the perp/bisector of SB is x=109 \n" ); document.write( "---------------- \n" ); document.write( "Find the intersection of the two perp/bisectors: \n" ); document.write( "Substitute x=109 into the perp/bisector of LS: \n" ); document.write( "y = (-113/108)(109)-214.959333 \n" ); document.write( "y = -329.0056295 \n" ); document.write( "----------- \n" ); document.write( "The circumcenter is (109,-329.0056295) \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |