document.write( "Question 130120: ok so my question is how can you still use the \"answer\" you get from the Quadratic formula to find the vertex? And this is what i did... \r
\n" ); document.write( "\n" ); document.write( "Problem: y= x^2-4x+6
\n" ); document.write( "i used the quadratic formula...
\n" ); document.write( "x= 4(+or-) \"+sqrt%28+4%5E2-4%281%29%286%29+%29+\" / 2(1)\r
\n" ); document.write( "\n" ); document.write( "and got x= 2 - 1.415i and x= 2 + 1.415i \r
\n" ); document.write( "\n" ); document.write( "how can i use those conjugate pairs to find the vertex?
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Algebra.Com's Answer #95050 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To find the x-coordinate of the vertex, simply average the two roots.\r
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\n" ); document.write( "\n" ); document.write( "\"2+-+1.415i%2B+2+%2B+1.415i\" Add the two roots\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2B2%29+%2B%281.415i-+1.415i%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"4+-+0i\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"4\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So it turns out that when you add any two complex conjugates together you will get a real answer.\r
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\n" ); document.write( "\n" ); document.write( "Now divide the answer by 2\r
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\n" ); document.write( "\n" ); document.write( "\"4%2F2=2\"\r
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\n" ); document.write( "\n" ); document.write( "So the x-coordinate of vertex is 2\r
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\n" ); document.write( "\n" ); document.write( "note:\r
\n" ); document.write( "\n" ); document.write( "Remember the quadratic formula is \r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\" and the formula for the x-coordinate of the vertex is \"x=-b%2F%282a%29\". Notice if you add the two roots the square root part cancels out to to give you \"-b%2F%282a%29\". So this shows how the quadratic formula and the vertex are related.
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