document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130101>Question 130101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> STANDARD QUALITY COFFEE FOR $18.00/KG AND PRIME QUALITY COFE SELLS FOR $24.00/KG. WHAT QUANTITY OF EACH SHOULD BE COMBINED TO PRODUCE 40KG OF A BLEND TO SELL FOR $22.50/KG? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95030 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24x+18(40-x)=22.50*40<BR>\n" );
document.write( "24x+720-18x=900<BR>\n" );
document.write( "6x=900-720<BR>\n" );
document.write( "6x=180<BR>\n" );
document.write( "x=180/6<BR>\n" );
document.write( "x=30 kg of $24 coffee is needed.<BR>\n" );
document.write( "40-30=10 kg of $18 coffee is needed.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "24*30=18*10=900<BR>\n" );
document.write( "720+180=900<BR>\n" );
document.write( "900=900 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );