document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130040>Question 130040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "solve the following system of equations by the substitution method:\r<BR>\n" );
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document.write( "4x=3y+30  3y-5x=-33\r<BR>\n" );
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document.write( "after substituting, find the remaining equation and the y coordinate of the solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95017 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3Y-5X=-33 OR 3Y=5X-33 NOW REPLACE 3Y IN THE OTHER EQUATION BY (5X-33) & SOLVE FOR X:<BR>\n" );
document.write( "4X=(5X-33)+30<BR>\n" );
document.write( "4X=5X-33+30<BR>\n" );
document.write( "4X-5X=-3<BR>\n" );
document.write( "-X=-3<BR>\n" );
document.write( "X=-3/-1<BR>\n" );
document.write( "X=3<BR>\n" );
document.write( "3Y=5*3-33<BR>\n" );
document.write( "3Y=15-33<BR>\n" );
document.write( "3Y=-18<BR>\n" );
document.write( "Y=-18/3<BR>\n" );
document.write( "Y=-6 ANSWER.<BR>\n" );
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