document.write( "Question 130095: Jules works part time at the bulk barn. She mixed one nut type selling at $2.20/kg with another selling at $2.40/kg. If 100kg were mixed and sold for $2.28/kg, how much of each type of nut mixture was used? \n" ); document.write( "
Algebra.Com's Answer #95008 by stanbon(75887) ![]() You can put this solution on YOUR website! Jules works part time at the bulk barn. She mixed one nut type selling at $2.20/kg with another selling at $2.40/kg. If 100kg were mixed and sold for $2.28/kg, how much of each type of nut mixture was used? \n" ); document.write( "----------------------- \n" ); document.write( "2.20 nut DATA: \n" ); document.write( "Let the amt. be \"x\" ; value is 2.20x dollars \n" ); document.write( "------------------------ \n" ); document.write( "2.40 nut DATA: \n" ); document.write( "Let the amt. be \"100-x\" ; value is 2.4(100-x)= 240-2.4x dollars \n" ); document.write( "----------------------- \n" ); document.write( "Mixture DATA: \n" ); document.write( "Amt o 100 kg ;value = 2.28*100 = 228 dollars \n" ); document.write( "------------------------ \n" ); document.write( "EQUATION: \n" ); document.write( "value + value = 228 dollars \n" ); document.write( "2.20x + 240-2.4x = 228 \n" ); document.write( "-0.2x = -12 \n" ); document.write( "x = 60 (amount of $2.20 nuts in the mixture) \n" ); document.write( "100-x = 40 (amount of $2.40 nuts in the mixture \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |