document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130068>Question 130068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An antique dealer found a 14K gold statue at an auction.  In order to maximize profits from this statue, it was melted down with cheap 6K gold trinkets to produce 8K gold replica.  If the replica has a mass of 3.2Kg, what were the masses of the statue and the trinkets used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94991 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94991\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 14x+6(x-3.2)=8*3.2<BR>\n" );
document.write( "14x+6x-19.2=25.6<BR>\n" );
document.write( "20x=25.6+19.2<BR>\n" );
document.write( "20x=44.8<BR>\n" );
document.write( "x=44.8/20<BR>\n" );
document.write( "x=2.24 kg was the weight of the statue.<BR>\n" );
document.write( "3.2-2.24=.96 kg is the amount of the 6K gold used.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "14*2.24+6*2.24-19.2=25.6<BR>\n" );
document.write( "31.36+13.44-19.2=25.6<BR>\n" );
document.write( "25.6=25.6<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );