document.write( "Question 19628: The question:\r
\n" ); document.write( "\n" ); document.write( "Suppose that the length of a rectangle is one and one-third times as long as its width. The area of the rectangle is 48 square centimeters. Find the length and width of the rectangle. \r
\n" ); document.write( "\n" ); document.write( "I need help devising/solving the equation:\r
\n" ); document.write( "\n" ); document.write( "a=lw
\n" ); document.write( "48=(1 and 1/3)(L)(W)
\n" ); document.write( "

Algebra.Com's Answer #9499 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
Suppose that the length of a rectangle is one and one-third times as long as its width. The area of the rectangle is 48 square centimeters. Find the length and width of the rectangle. \r
\n" ); document.write( "\n" ); document.write( "I need help devising/solving the equation:\r
\n" ); document.write( "\n" ); document.write( "a=lw...VERY GOOD
\n" ); document.write( "48=(1 and 1/3)(L)(W)...ALMOST CORRECT..THE BEST WAY IS
\n" ); document.write( "LET WIDTH =W
\n" ); document.write( "LENGTH=one and one-third times as long as its width.=(1 and 1/3)(W)..=(4/3)(W).
\n" ); document.write( "=4W/3
\n" ); document.write( "SO AREA =L*W=(4W/3)*W=48
\n" ); document.write( "W*W=48*3/4=36
\n" ); document.write( "W=6 CM
\n" ); document.write( "L=4W/3=4*6/3=8 CM
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