document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130076>Question 130076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Draw one rectangle that has both a perimeter of 18 centimeters and an area of 18 square centimeters. Label the width and length </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94989 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x*y=18 or x=18/y<BR>\n" );
document.write( "2x+2y=18 now replace x by (18/y) & solve for y:<BR>\n" );
document.write( "2(18/y)+2y=18<BR>\n" );
document.write( "36/y+2y=18<BR>\n" );
document.write( "(36+2y^2)/y=18 now cross multiply<BR>\n" );
document.write( "36+2y^2=18y<BR>\n" );
document.write( "2y^2-18y+36=0<BR>\n" );
document.write( "2(y^2-9y+18)=0<BR>\n" );
document.write( "2(y-6)(y-3)=0<BR>\n" );
document.write( "y-6=0<BR>\n" );
document.write( "y=6 answer<BR>\n" );
document.write( "y-3=0<BR>\n" );
document.write( "y=3 answer.<BR>\n" );
document.write( "so the sides of this rectangle are 3 & 6 cm.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "3*6=18<BR>\n" );
document.write( "2*(18/6)+2*3=18<BR>\n" );
document.write( "36/6+6=18<BR>\n" );
document.write( "12+6=18<BR>\n" );
document.write( "18=18<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );