document.write( "Question 130030: I have this last story problem to do and am confused, can someone help?\r
\n" ); document.write( "\n" ); document.write( "Use the formula 1 over f = 1 over o + 1 over i to find the image distance i for an object that is 2,000,000 mm from a 250-mm telephoto lens.\r
\n" ); document.write( "\n" ); document.write( "So confused, can someone help? Thanks
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Algebra.Com's Answer #94980 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given the formula for a lens:
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\n" ); document.write( "\"1%2Ff+=+1%2Fo+%2B+1%2Fi\"
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\n" ); document.write( "In which f is the focal length of the lens, o is the object distance from the lens, and
\n" ); document.write( "i is the image distance from the lens.
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\n" ); document.write( "For this problem, you are told that f, the focal length of the lens, if 250 mm and that o
\n" ); document.write( "the object distance from the lens is 2,000,000 mm. (The object is 2,000 meters away, which
\n" ); document.write( "is a long distance compared to the focal length of the lens.)
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\n" ); document.write( "All units in this equation will be mm. Substitute the two values you are given (one for f
\n" ); document.write( "and one for o) and you have:
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\n" ); document.write( "\"1%2F250+=+1%2F2000000+%2B+1%2Fi\"
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\n" ); document.write( "Let's get rid of the denominator 2000000 by multiplying both sides (all terms) of this equation
\n" ); document.write( "by 2000000 and the equation then becomes:
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\n" ); document.write( "\"2000000%2F250+=+1+%2B+2000000%2Fi\"
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\n" ); document.write( "Do the division on the left side by dividing 250 into 2000000 and the equation becomes:
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\n" ); document.write( "\"8000+=+1+%2B+2000000%2Fi\"
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\n" ); document.write( "Get rid of the 1 on the right side by subtracting 1 from both sides and this reduces the
\n" ); document.write( "equation to:
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\n" ); document.write( "\"7999+=+2000000%2Fi\"
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\n" ); document.write( "Get rid of the denominator i on the right side by multiplying both sides of the equation (all terms)
\n" ); document.write( "by i to get:
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\n" ); document.write( "\"7999i+=+2000000\"
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\n" ); document.write( "Solve for i by dividing both sides of the equation by 7999 and you have:
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\n" ); document.write( "\"i+=+2000000%2F7999\"
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\n" ); document.write( "Do the division on the right side (use a calculator) and you find that the image distance is
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\n" ); document.write( "\"i+=+250.0312539\"
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\n" ); document.write( "So the answer is that the image distance from the lens is about 250.03 mm.
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\n" ); document.write( "If you are into physics and science, what does this tell you? It says that as long as the
\n" ); document.write( "object is far away from the lens, the image will always be about 250 mm from the lens. Therefore,
\n" ); document.write( "the image will be pretty much in focus if the film or the digital sensors plates for digital
\n" ); document.write( "cameras are located about 250 mm behind the lens. This would be a pretty good sized camera
\n" ); document.write( "since 250 meters behind the lens is nearly 10 inches, so the camera would be around
\n" ); document.write( "10 inches deep.\r
\n" ); document.write( "\n" ); document.write( "Maybe this will make sense to you. It does to serious photographers.
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\n" ); document.write( "Hope this helps you to learn a little about math and also some about the physical
\n" ); document.write( "characteristics of lenses.
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