document.write( "Question 130030: I have this last story problem to do and am confused, can someone help?\r
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document.write( "Use the formula 1 over f = 1 over o + 1 over i to find the image distance i for an object that is 2,000,000 mm from a 250-mm telephoto lens.\r
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document.write( "So confused, can someone help? Thanks \n" );
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Algebra.Com's Answer #94980 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given the formula for a lens: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "In which f is the focal length of the lens, o is the object distance from the lens, and \n" ); document.write( "i is the image distance from the lens. \n" ); document.write( ". \n" ); document.write( "For this problem, you are told that f, the focal length of the lens, if 250 mm and that o \n" ); document.write( "the object distance from the lens is 2,000,000 mm. (The object is 2,000 meters away, which \n" ); document.write( "is a long distance compared to the focal length of the lens.) \n" ); document.write( ". \n" ); document.write( "All units in this equation will be mm. Substitute the two values you are given (one for f \n" ); document.write( "and one for o) and you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Let's get rid of the denominator 2000000 by multiplying both sides (all terms) of this equation \n" ); document.write( "by 2000000 and the equation then becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Do the division on the left side by dividing 250 into 2000000 and the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Get rid of the 1 on the right side by subtracting 1 from both sides and this reduces the \n" ); document.write( "equation to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Get rid of the denominator i on the right side by multiplying both sides of the equation (all terms) \n" ); document.write( "by i to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Solve for i by dividing both sides of the equation by 7999 and you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Do the division on the right side (use a calculator) and you find that the image distance is \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "So the answer is that the image distance from the lens is about 250.03 mm. \n" ); document.write( ". \n" ); document.write( "If you are into physics and science, what does this tell you? It says that as long as the \n" ); document.write( "object is far away from the lens, the image will always be about 250 mm from the lens. Therefore, \n" ); document.write( "the image will be pretty much in focus if the film or the digital sensors plates for digital \n" ); document.write( "cameras are located about 250 mm behind the lens. This would be a pretty good sized camera \n" ); document.write( "since 250 meters behind the lens is nearly 10 inches, so the camera would be around \n" ); document.write( "10 inches deep.\r \n" ); document.write( "\n" ); document.write( "Maybe this will make sense to you. It does to serious photographers. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to learn a little about math and also some about the physical \n" ); document.write( "characteristics of lenses. \n" ); document.write( ". \n" ); document.write( " |