document.write( "Question 130032: hi
\n" ); document.write( "im dawn marie
\n" ); document.write( "my question is
\n" ); document.write( "jen was 25 years old when her son was born, her present age is 7 years less than 3 times her son's present age. how old is jen now?
\n" ); document.write( "please answer my question...
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Algebra.Com's Answer #94978 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
When Jen's son was born she was 25 yrs old and her son was 0 (not yet 1). Let x be the number of
\n" ); document.write( "years that have gone by since then. This means that Jen is now 25 + x years old and her
\n" ); document.write( "son is x years old.
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\n" ); document.write( "If you take 3 times her sons present age and subtract 7 from that, the result is Jen's present age.
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\n" ); document.write( "We can write an equation that says exactly that: three times her son's age less 7 is 3x - 7
\n" ); document.write( "and this is equal to Jen's present age of 25 + x. In equation form this is:
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\n" ); document.write( "3x - 7 = 25 + x
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\n" ); document.write( "Get rid of the x on the right side by subtracting x from both sides and you have:
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\n" ); document.write( "2x - 7 = 25
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\n" ); document.write( "Get rid of the -7 on the left side by adding 7 to both sides to reduce the equation to:
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\n" ); document.write( "2x = 32
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\n" ); document.write( "Solve for x by dividing both sides of this equation by 2 and you have:
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\n" ); document.write( "x = 16
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\n" ); document.write( "16 years have gone by since her son was born. Since Jen was 25 when he was born, that means
\n" ); document.write( "that Jen is now 41 years old (25 + 16).
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\n" ); document.write( "Check: is 41 equal to three times her son's age less 7 years. Her son is 16 and 3 times 16
\n" ); document.write( "is 48 and take away 7 results in 41. Works OK, so our answer is correct.
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\n" ); document.write( "Hope this helps you to understand the problem.
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