document.write( "Question 130015: Draw a graph of y=2x for x-values from 0 to 5 (< x > 5)
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Algebra.Com's Answer #94973 by bucky(2189)\"\" \"About 
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First graph the given equation y = 2x
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\n" ); document.write( "This equation is in the slope intercept form y = mx + b in which m (the multiplier of x) is
\n" ); document.write( "the slope of the line and b the constant is the value on the y-axis where the graph intersects
\n" ); document.write( "(crosses) the y-axis.
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\n" ); document.write( "By comparing the given equation with the slope intercept form you can tell that the graph
\n" ); document.write( "should have a slope of 2 because 2 is the multiplier of x. The constant b must equal zero
\n" ); document.write( "because there is no constant on the right side of the given equation. This tells you that the
\n" ); document.write( "graph crosses the y-axis at the origin because the y value at the origin is zero.
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\n" ); document.write( "So you know the graph crosses through the origin and has a slope of 2. You can also use
\n" ); document.write( "some points to determine the graph. For example, you can let x = 10. Plug this value for
\n" ); document.write( "x into the given equation to find the corresponding value of y and you get:
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\n" ); document.write( "y = 2x = 2(10) = 20
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\n" ); document.write( "With x = 10 and the corresponding value of y = 20, you can mark the point (10,20) and
\n" ); document.write( "it will be on the graph. Put a straight edge on the origin and the point (10, 20) and
\n" ); document.write( "extend a line through those two points. That is the graph and it should look like this:
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\n" ); document.write( "\"graph%28400%2C+400%2C+-15%2C+15%2C+-20%2C20%2C2x%29\"
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\n" ); document.write( "But the problem tells you that you are only interested in that portion of the graph where
\n" ); document.write( "x has values from 0 to +5. Go along the x axis to the value +5. Draw a vertical line through
\n" ); document.write( "+5 to the point where it intersects the graph. (That point will be (5,10)). Erase the
\n" ); document.write( "part of the graph that is to the right of that vertical line. Then go back to the origin
\n" ); document.write( "where the value of x is zero. Erase all of the graph that lies to the left of that point
\n" ); document.write( "(that is erase that part of the graph that is in the third quadrant ... left of the y-axis.
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\n" ); document.write( "What you have left is a graph that starts at the origin and goes to the point (5,10) and
\n" ); document.write( "that's it. That should be what you are looking for.
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