document.write( "Question 129967This question is from textbook A Graphical Approach to College Algebra
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document.write( ": a. i^102\r
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document.write( "b. i^-15 \n" );
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Algebra.Com's Answer #94967 by edjones(8007) You can put this solution on YOUR website! i^1=i \n" ); document.write( "i^2=-1 \n" ); document.write( "i^3=-i \n" ); document.write( "i^4=1 \n" ); document.write( ". \n" ); document.write( "a. i^102 \n" ); document.write( "102/4=25 2/4 \n" ); document.write( "Since the remainder is 2 the answer is 2nd on the list above: -1. \n" ); document.write( ". \n" ); document.write( "i^-15 \n" ); document.write( "=1/i^15 \n" ); document.write( "15/4=3 3/4 \n" ); document.write( "Since the remainder is 3 the answer is 3rd on the list above: 1/-i \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |