document.write( "Question 129984: A person traveling 4 hr by plane and 25 hr by ship covers 1580 miles. If the speed of the plane had been one-half of the actual speed and the speed of the ship had been one-fourth greater, the person would have traveled only 1315 miles in the same length of time. Find the speeds of the plane and the ship..
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Algebra.Com's Answer #94956 by stanbon(75887)\"\" \"About 
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A person traveling 4 hr by plane and 25 hr by ship covers 1580 miles. If the speed of the plane had been one-half of the actual speed and the speed of the ship had been one-fourth greater, the person would have traveled only 1315 miles in the same length of time. Find the speeds of the plane and the ship..
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\n" ); document.write( "Original Plane DATA:
\n" ); document.write( "Rate = x mph ; Time = 4 hr. : Distance = rt = 4x miles
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\n" ); document.write( "Original Ship DATA:
\n" ); document.write( "Distance = 1580-4x miles ; Time = 25 hrs. ; Rate = d/t = (1580-4x)/25 mph
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\n" ); document.write( "New Plane DATA:
\n" ); document.write( "Rate = x/2 mph ; Time = 4 hr ; Distance = rt = 2x miles
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\n" ); document.write( "New Ship DATA:
\n" ); document.write( "Rate = (3/2)(1580-4x)/25 mph ; Time = 25 hrs. ; Dist. = rt = (3/2)(1580-4x) mi.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "(3/2)(1580-4x) = 1315
\n" ); document.write( "1580-4x = 876.33333333
\n" ); document.write( "4x = 703.333333333
\n" ); document.write( "x = 175.8333333...(plane speed)
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\n" ); document.write( "Ship speed = (1580-4x)/25 mph
\n" ); document.write( "(1580-4*175.833333333)/25) = 35.07 mph (ship speed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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