document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19622>Question 19622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve this equation.  I have tried numerous time, getting frustrated.<BR>\n" );
document.write( "Write the equation of the line which passes through the point (2,1) and is parallel to the line with equation y=5/2x+6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9493 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> very simple topic really.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The critical thing you need to remember is y=mx+c. Any straight line will/can be written like this, where m is the gradient and c is the y-intercept.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So, we have the line y = (5/2)x + 6... it is written in standard form, so its gradient is 5/2. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The line we are asked for, is parallel to this one. Parallel means the same gradient, so our line has m=5/2, so we have...\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y = (5/2)x + c\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now we need to know c. Well to do that, we need to know x and y, ie a point on the line...which surprise surprise, we do, namely (2,1). So, putting these into the equation, we get\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1 = (5/2)(2) + c<BR>\n" );
document.write( "--> 1 = 5 + c<BR>\n" );
document.write( "--> -4 = c\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "so, that is it, our equation is y = (5/2)x - 4, which we may write without fractions as 2y = 5x - 8.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "jon.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );