document.write( "Question 129924: I need help with solving this logarithmic equation\r
\n" ); document.write( "\n" ); document.write( "log x+log(x+3)=1
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Algebra.Com's Answer #94891 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%2810%2C%28x%29%29%2Blog%2810%2C%28x%2B3%29%29=1\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2Cx%28x%2B3%29%29=1\" Combine the logs using the identity \"log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29=log%28b%2C%28A%2AB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"10%5E%281%29=x%28x%2B3%29\" Rewrite the equation using the property: \"log%28b%2C%28x%29%29=y\" ====> \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"10=x%28x%2B3%29\" Evaluate \"10%5E%281%29\" to get \"10\"\r
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\n" ); document.write( "\n" ); document.write( "\"10=x%5E2%2B3x\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2%2B3x-10\" Subtract 10 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0=%28x%2B5%29%28x-2%29\" Factor the right side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5=0\" or \"x-2=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=-5\" or \"x=2\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our possible answers are\r
\n" ); document.write( "\n" ); document.write( " \"x=-5\" or \"x=2\" \r
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\n" ); document.write( "\n" ); document.write( "However, if you plug in \"x=-5\", you'll have a negative number in the log.\r
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\n" ); document.write( "\n" ); document.write( "So our only answer is \"x=2\"
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