document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129455>Question 129455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5 years ago a son was 1/3 the age of his father.  5 years from now he will be 1/2 the age of his father.  How old are both now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94883 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=\"son now\" and y=\"father now\"\r<BR>\n" );
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document.write( "\"5 years ago a son was 1/3 the age of his father\" __ 3(x-5)=y-5 __ 3x-15=y-5\r<BR>\n" );
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document.write( "\"5 years from now he will be 1/2 the age of his father\" __ 2(x+5)=y+5 __ 2x+10=y+5\r<BR>\n" );
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document.write( "subtracting second equation from first __ x-25=-10\r<BR>\n" );
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document.write( "substitute the value of x into either equation to find y </SPAN>\n" );
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