document.write( "Question 129899: \r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 5 less than twice the width. The area of the rectangle is 7 square units. Find the dimensions of the rectangle. Hint: quadratic formula!
\n" ); document.write( "my work so far: 2w-5=L w(2w-5)=7
\n" ); document.write( "
\n" ); document.write( " w(2w)-5w-7=0\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #94858 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
L=2W-5
\n" ); document.write( "W(2W-5)=7
\n" ); document.write( "2W^2-5W-7=0
\n" ); document.write( "(2W-7)(W+1)=0
\n" ); document.write( "2W-7=0
\n" ); document.write( "2W=7
\n" ); document.write( "W=7/2
\n" ); document.write( "W=3.5 ANSWR FOR THE WIDTH.
\n" ); document.write( "L=2*3.5-5
\n" ); document.write( "L=7-5
\n" ); document.write( "L=2
\n" ); document.write( "PROOF:
\n" ); document.write( "3.5(2*3.5-5)=7
\n" ); document.write( "3.5(7-5)=7
\n" ); document.write( "3.5*2=7
\n" ); document.write( "7=7\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );