document.write( "Question 129878: Airplane A travels 2800 km at a certain speed. Airplane B travels 2000 km at a speed 50 km/hr faster than plane A and in 3 hours less time. What is the traveling speed of each plane? \n" ); document.write( "
Algebra.Com's Answer #94852 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt;r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let r=speed of plane A
\n" ); document.write( "Then r+50=speed of plane B\r
\n" ); document.write( "\n" ); document.write( "Time for plane A=d/r=2800/r
\n" ); document.write( "Time for plane B=d/r=2000/(r+50)\r
\n" ); document.write( "\n" ); document.write( "Now we are told that the travelling time for plane B is three hours less than the travelling time for plane A, so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "2000/(r+50)=(2800/r)-3 multiply each term by r(r+50)\r
\n" ); document.write( "\n" ); document.write( "2000r=2800(r+50)-3r(r+50) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "2000r=2800r+140000-3r^2-150r subtract 2000r from each side\r
\n" ); document.write( "\n" ); document.write( "2000r-2000r=2800r-2000r+140000-3r^2-150r collect like terms\r
\n" ); document.write( "\n" ); document.write( "0=650r+140000-3r^2 multiply each term by -1\r
\n" ); document.write( "\n" ); document.write( "3r^2-650r-140000=0 quadratic in standard form solve using the quadratic formula\r
\n" ); document.write( "\n" ); document.write( "\"r+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"r+=+%28650+%2B-+sqrt%28+422500%2B4%2A3%2A140000+%29%29%2F%282%2A3%29+\"
\n" ); document.write( "\"r+=+%28650+%2B-+sqrt%28+2102500+%29%29%2F%286%29+\"
\n" ); document.write( "\"r+=+%28650+%2B-1450%29%2F%286%29+\"\r
\n" ); document.write( "\n" ); document.write( "Disregard the negative value for r; rates are positive in this case
\n" ); document.write( "\"r+=+%28650+%2B1450%29%2F%286%29+\"
\n" ); document.write( "\"r+=+%282100%29%2F%286%29+\"
\n" ); document.write( "\"r+=+350+\" km/hr-------------------speed of plane A\r
\n" ); document.write( "\n" ); document.write( "\"r%2B50=350%2B50=400\"km/hr--------------------speed of plane B\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "Time for plane A=2800/350=8 hr
\n" ); document.write( "Time for plane B=2000/400=5 hr
\n" ); document.write( "8-5=3
\n" ); document.write( "3=3\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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