document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129873>Question 129873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem is from http://www.testprepreview.com/modules/algebra2.htm \r<BR>\n" );
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document.write( "If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94844 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Steven can do 1/5 of the job in 1 minute, Sue 1/10 and Jack 1/15 in 1 minute.<BR>\n" );
document.write( "Let j= the job.<BR>\n" );
document.write( "1/5 + 1/10 + 1/15<BR>\n" );
document.write( "6/30 + 3/30 + 2/30 = 11/30 of the job in 1 minute.<BR>\n" );
document.write( "30/11= 2 8/11 minutes to mix 20 drinks together.<BR>\n" );
document.write( "2 min 43.6 sec.<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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