document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129869>Question 129869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twice the difference of a number and 3 is equal to three times the sum of the number and 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94837 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the unknown number.<BR>\n" );
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document.write( "The difference of a number and 3 is x - 3<BR>\n" );
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document.write( "The sum of the number and 5 is x + 5<BR>\n" );
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document.write( "Twice the difference of a number and 3 is therefore 2(x - 3) <BR>\n" );
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document.write( "Three times the sum of the number and 5 is therefore 3(x + 5)<BR>\n" );
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document.write( "These last two terms are equal. In equation form this is:<BR>\n" );
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document.write( "2(x - 3) = 3(x + 5)<BR>\n" );
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document.write( "Perform the distributed multiplications on both sides. On the left side multiply the 2 times<BR>\n" );
document.write( "each of the terms in the set of parentheses. On the right side multiply the 3 times each<BR>\n" );
document.write( "of the terms in its set of parentheses. After these two multiplications the equation is:<BR>\n" );
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document.write( "2x - 6 = 3x + 15<BR>\n" );
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document.write( "Get rid of the 3x on the right side by subtracting 3x from both sides and you have:<BR>\n" );
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document.write( "-x - 6 = 15<BR>\n" );
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document.write( "Get rid of the -6 on the left side by adding 6 to both sides to get:<BR>\n" );
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document.write( "-x = 21<BR>\n" );
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document.write( "You are trying to solve for +x. To change the left side of this equation to +x multiply<BR>\n" );
document.write( "both sides by -1 and you change the equation to:<BR>\n" );
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document.write( "x = -21<BR>\n" );
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document.write( "Hope this helps you to understand the problem. <BR>\n" );
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