document.write( "Question 129861This question is from textbook Introductory Algebra
\n" );
document.write( ": A student walks and jogs to college each day. She averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog? \n" );
document.write( "
Algebra.Com's Answer #94825 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 5T+9(1-T)=8 \n" ); document.write( "5T+9-9T=8 \n" ); document.write( "-4T=-1 \n" ); document.write( "T=-1/-4 \n" ); document.write( "T=1/4 OR .25 HOURS FOR THE TIME WALKING \n" ); document.write( "1-1/4=3/4 OR .75 HOURS JOGGING. \n" ); document.write( "PROOF \n" ); document.write( "5*.25+9*.75=8 \n" ); document.write( "1.25+6.75=8 \n" ); document.write( "8=8 \n" ); document.write( " |