document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129847>Question 129847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Squareroot of 2x-5 + squareroot of 9+x=13\r<BR>\n" );
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document.write( "I square both sides and get 2x-5+9+x=169 and solve x=55 but it's wrong.  What am I missing?  Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94818 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a+b)^2=a^2+2ab+b^2\r<BR>\n" );
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document.write( "so \r<BR>\n" );
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document.write( "sqrt(2x-5)+sqrt(9+x)=13\r<BR>\n" );
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document.write( "2x-5+2sqrt(2x-5)sqrt(9+x)+9+x=169\r<BR>\n" );
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document.write( "3x+4+2sqrt(2x-5)sqrt(9+x)=169\r<BR>\n" );
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document.write( "3x-165 = -2sqrt(2x-5)sqrt(9+x)\r<BR>\n" );
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document.write( "(3x-165)^2=4(2x-5)(9+x)\r<BR>\n" );
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document.write( "if you need the rest please contact me\r<BR>\n" );
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