document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=129796>Question 129796</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Separate 116 into two parts, one of which shall be 3 times the other<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #94815 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=94815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=one part \r<BR>\n" );
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document.write( "Then 3x =the other part\r<BR>\n" );
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document.write( "Now we know that:\r<BR>\n" );
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document.write( "x+3x=116<BR>\n" );
document.write( "4x=116  divide both sides by 4\r<BR>\n" );
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document.write( "x=29----------------------one part\r<BR>\n" );
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document.write( "3x=3*29=87 the other part\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "3*29=87<BR>\n" );
document.write( "87=87\r<BR>\n" );
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document.write( "also\r<BR>\n" );
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document.write( "87+29=116\r<BR>\n" );
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document.write( "116=116\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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